Calculus
Lesson
23 The Fundamental Theorem of Calculus
and
The Mean Value Theorem for Integrals
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FTC: ,
where is the antiderivative of and
is continuous on
Examples:
MVT for integrals: remember that MVT tells us that there was a point on the
curve with the same slope as the average slope.
MVT for integrals tells us that there is a point on the function such that
the area found by is the same as the area under the curve
from to .
Formally, we say that there exists such that
as long as is continuous on .
What this is saying is that we can find a rectangle that has the same area as the curve. The
widths are the same. We can find such that the height is .
Note that there could be more than one value for .
We call the average value of the function. Using MVT for integrals, we can then find
the average value of the function by dividing both sides by .
Example: Find the average value of on the interval .
Example: Find the average value of on the interval .
Check for it to be continuous!!!!
Lastly, we have the 2nd Fundamental Theorem of Calculus:
(derive by using FTC)
This can be interpreted as figuring out how the area is changing!
Let g be a continuous function on an interval,
such that and
.
(a) What is the largest possible domain for ?
(b) Write an expression for .
(c)
(d)
On to Lesson 24 - Integration by Substitution