Calculus

Lesson 54

Taylor Polynomials

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                        Before we examine Taylor Polynomials, let's show that

                                                .

 

                                    Note that this formula only works at x=0!!!!

 

 

                        Let's call  and

 

 

            Note that    and       and    

 

 

 

                        So, it makes sense that the formula could be right.  In fact, this is a good

                        definition of equivalent functions at a single point.  If, at a given point, the

                        two functions have the same value, and all orders of derivatives evaluated at

                        that point also have the same value, then the two functions must be

                        equivalent near that point.

 

 

            So, we could actually derive this formula!  To approximate ,

                       

 

                        Since  and so on, then we must make sure the same

                        is true for  and so on.  Thus, we can see

                       

 

 

 

 

 

 

            This approximation will work well for numbers NEAR .

            Now, what if we are not looking near ?

 

                        We just do the same thing!  

                                    and so on.

 

            Where

 

                        If we then solve the equations to find all of the ans.

 

                       

 

                        Putting it all together, we come up with the definition of a Taylor Series:

 

           

            Note, then, that a good choice for  will be a number for which we know  and is near the x-values we want to look at.

 

            Examples:     Find  through  for  about .

                                    Find  for  about  (Maclauren polynomial).

                                    Find  for  about .

                                    Find an approximation for  using the Maclauren polynomial

                                                to 5th order  (use  about ).

                       

 

 

            Now how accurate is this approximation?  Let's say that

 

                        where  is evaluated at .  The error is , where

                        .  Note that this is just the next term of the

                        Taylor Polynomial, evaluated at .  If we plug all possible s into the

                        remainder, we have a range of error for our approximation.  It turns out that

                        there will always be a possible  such that   (or )

 

 

                        Taylor's Theorem says that there exists some  for which the above is true.

                        Therefore, if we plug in the bounds for , we get the range of errors.

 

 

            Example:  Find  using the Maclauren polynomial to 5th order , and

                                    determine the possible range of error on the approximation.

 

         

 

 

                            about

 

                       

                       

                       

 

 

                                       where  

                                    since  and  (Maclauren polynomial!)  

                                    The largest error would occur if , so

 

                                   

 

 

            Therefore, we can conclusively say that:

 

           

 

                        So to 6 decimal places,

                        According to our calculators,

 

 

 

 

 

 

            Example:  Using 3rd order Maclauren series, find  and estimate error

                                    (remembering ).

       

                                               

 

                        So

 

                        The remainder is   where .

 

                        The largest remainder occurs when

 

                          Now, we don't know what  is, since

                        that's what we're trying to find!  However, we can definitely say that

                        , so let's stick that in. 

 

 

                        Therefore,

 

             

 

 

                        So to 5 decimal places,

                        According to our calculators: 

 

On to Lesson 55 - Power Series

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